example 14.9

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kane_jajieh_3F
Posts: 17
Joined: Wed Sep 21, 2016 2:58 pm

example 14.9

Postby kane_jajieh_3F » Mon Feb 06, 2017 2:19 pm

in example 14.9 why is the nr value equal to 2? shouldn't it be 1 as indicated by the redox reaction equation?

Michelle_Li_1H
Posts: 32
Joined: Wed Sep 21, 2016 3:00 pm

Re: example 14.9

Postby Michelle_Li_1H » Mon Feb 06, 2017 3:36 pm

If you break down the redox reaction equation into the half reactions, then you'll get

2Ce^4+ --> 2Ce^3+

On the left hand side, the charge will be 8+, while the right will be 6+. To get a balanced half reaction, you'll have to add 2 moles of e- to the left hand side, which is where the 2 moles in your question comes from. You would also get 2e- with the other half reaction with I.
Keep in mind the coefficients when calculating the charges.

Hope this helps!


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