Textbook Question 14.3 D

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Mannat Sukhija 1E
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Textbook Question 14.3 D

Postby Mannat Sukhija 1E » Thu Feb 09, 2017 2:56 pm

In the reaction


why does CL2(g) serve as both the oxidation and reducing agent since it is being reduced?

Thank you in advance!

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Re: Textbook Question 14.3 D

Postby Sylvia_Cai_3D » Thu Feb 09, 2017 3:47 pm

The oxidation number of Cl2 is 0 in the reactants. The oxidation number of Cl in HClO is +1 and the oxidation number of Cl in Cl- is -1. So the Cl2 can serving as both an oxidizing and reducing agent.

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