Self Test 14.2 B

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feodora_r_3d
Posts: 16
Joined: Wed Sep 21, 2016 2:59 pm

Self Test 14.2 B

Postby feodora_r_3d » Fri Feb 10, 2017 3:59 pm

Hi! I am a bit confused with this question: When iodide ions react with iodate ions in basic aqueous solution, triiodide ions, I3- , are formed. Write the net ionic equation for the reaction. (Note that the same product is obtained in each half-reaction.)
I got the equation like this:
I-(aq) + IO3-(aq) --> I3-

I got stuck afterwards because I'm a bit confused of how to determine the oxidation and reduction equations with only one product ...

Thank you in advance!

Annie Duong 3L
Posts: 13
Joined: Fri Jul 15, 2016 3:00 am

Re: Self Test 14.2 B

Postby Annie Duong 3L » Fri Feb 10, 2017 5:16 pm

The equation for the reaction of iodide with iodate should be:



Does that make it easier to figure out the oxidation/reduction part?

feodora_r_3d
Posts: 16
Joined: Wed Sep 21, 2016 2:59 pm

Re: Self Test 14.2 B

Postby feodora_r_3d » Fri Feb 10, 2017 9:46 pm

From the equation you write, yes I could identify the reduction and oxidation!! But could you explain how you can come up with that equation? Thankyou!


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