Review from 14a

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J_Rodriguez_Dis2k
Posts: 25
Joined: Fri Sep 25, 2015 3:00 am

Review from 14a

Postby J_Rodriguez_Dis2k » Sun Feb 12, 2017 9:00 pm

how do we find the concentration of K or Q again ?

Riley Seid 1L
Posts: 13
Joined: Wed Sep 21, 2016 2:55 pm

Re: Review from 14a

Postby Riley Seid 1L » Sun Feb 12, 2017 9:04 pm

K is usually given. Q, as in the reaction quotient, is given by the concentration of products over the concentration of reactants. If K=Q, the reaction is at equilibrium.

EllisJang2O
Posts: 18
Joined: Wed Sep 21, 2016 2:55 pm

Re: Review from 14a

Postby EllisJang2O » Sun Feb 12, 2017 9:04 pm

Reaction quotient Q = [P]/[R]
More specifically, aA + bB ⇌ cC + dD
Q = [C]^c[D]^d/[A]^a[B]^b

For example, N2(g) + 3H2(aq) ⇌ 2NH3(g)
Q = [NH3(g)]^2/[N2(g)][H2(aq)]^3

Equilibrium constant K is the same format but at equilibrium concentrations.


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