2016 Midterm Q3

Moderators: Chem_Mod, Chem_Admin

Posts: 21
Joined: Fri Jul 22, 2016 3:00 am

2016 Midterm Q3

Postby Christina_F_3F » Tue Feb 14, 2017 2:47 am

"1.00 mile of ideal gas is compressed reversibly and isothermally at constant temperature T=500K and w= 1000 J. Find the following quantities for this process."
For question 3A, you are asked to find delta U. I'm just really confused why delta U is equal to zero?
When I did this problem, I figured that delta U = q + w. Since q=mc•deltaT, and delta T here is zero, then wouldn't delta U be 1000 J and q = 0?

Posts: 26
Joined: Fri Jul 22, 2016 3:00 am
Been upvoted: 1 time

Re: 2016 Midterm Q3

Postby Khang_Tran_1O » Tue Feb 14, 2017 3:41 am

If you look back at pg. 30 in the course reader,for ideal gas, delta U = 3/2*n*R*delta T and since it is isothermal, meaning that there is no temperature change, then delta T = 0. It being 0 then makes delta U = 0 also.

Return to “Balancing Redox Reactions”

Who is online

Users browsing this forum: No registered users and 1 guest