2013 Final #4

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Michelle_Nguyen_3F
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Joined: Wed Sep 21, 2016 2:59 pm

2013 Final #4

Postby Michelle_Nguyen_3F » Mon Mar 13, 2017 4:08 pm

Given , how would we write the half reactions? Thank you!

Andrea Medina 1A
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Joined: Wed Sep 21, 2016 2:58 pm

Re: 2013 Final #4

Postby Andrea Medina 1A » Mon Mar 13, 2017 10:09 pm

I have a similar question how would we know the moles of electrons if we are not given the charges and Fe is a transition metal?

Pauline Tze 3B
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Re: 2013 Final #4

Postby Pauline Tze 3B » Tue Mar 14, 2017 10:52 pm

2Fe(s) + 2H2O --> 2Fe(OH)2(s) + 4e-
pay attention to the charge for Fe as Fe is oxidized from 0 to +2
O2 + 4e- ----> 2Fe(OH)2(s)
pay attention to the charge for O as O is reduced from 0 to -2

Paul Adkisson 1D
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Re: 2013 Final #4

Postby Paul Adkisson 1D » Wed Mar 15, 2017 11:00 pm

Wait, How would that work? The reduction reaction isn't balanced (Fe on products but not in reactants). I also had trouble determining n for this question.

alvarado_natalie_2H
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Re: 2013 Final #4

Postby alvarado_natalie_2H » Sat Mar 18, 2017 2:29 pm

So we would calculate the electron number from the changes in charges seen in the corresponding half reactions?


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