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9.3b

Posted: Sat Feb 17, 2018 11:19 am
by Gabriela Carrillo 1B
After balancing the half reactions I had 5 electrons for the reduction and 2 for the oxidation. Is the only way to balance these by multiplying by their LCM??

Re: 9.3b

Posted: Sat Feb 17, 2018 11:58 am
by Eli Aminpour 2K
that is usually how you do it.