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It will become more obvious that oxygen is being reduced once you balance the hydrogens and oxygens in the equation. The half reaction isn't balanced so it is difficult to tell what is happening. The balanced reaction should look like H2O (l) + O3 (g) + 2e- -> O2 (g) + 2OH- (aq). The oxygen is going from having a neutral charge to a minus 2 charge, as there are 2OH-. This would be why the 2 electrons appear on the left side of the equation.
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