14.5a

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Angela 1K
Posts: 80
Joined: Fri Sep 29, 2017 7:05 am

14.5a

Postby Angela 1K » Mon Feb 19, 2018 9:30 pm

Can someone please walk me through how to do this problem?
It's asking to balance the equation O3(aq) + Br-(aq) --> O2(g) + BrO3-.
I'm just confused on how to balance this when the atoms being oxidized and reduced are both present in the same molecule in the products.

Jason Liu 1C
Posts: 52
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.5a

Postby Jason Liu 1C » Mon Feb 19, 2018 9:46 pm

The atoms being oxidized and reduced actually aren't both present in the same molecule in the products. The oxidation half reaction is O3 --> O2 and the reduction half reaction is Br- --> BrO3-

Angela 1K
Posts: 80
Joined: Fri Sep 29, 2017 7:05 am

Re: 14.5a

Postby Angela 1K » Mon Feb 19, 2018 9:55 pm

Jason Liu 1C wrote:The atoms being oxidized and reduced actually aren't both present in the same molecule in the products. The oxidation half reaction is O3 --> O2 and the reduction half reaction is Br- --> BrO3-


I don't understand how O3 is being reduced to O2 if the oxidation state of both oxygen atoms are 0.

Leanne Wong 1H
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Joined: Tue Oct 10, 2017 7:13 am
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Re: 14.5a

Postby Leanne Wong 1H » Wed Feb 21, 2018 4:47 am

O3 is being reduced because you have to balance the half reaction of O3 -> O2 which would have H2O on the O2 side which would then force there to be two hydrogen ions on the ozone side which means that it would also have 2e- on that side too. Therefore, ozone is reduced since it is gaining electrons.

Erik Khong 2E
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Joined: Fri Sep 29, 2017 7:07 am

Re: 14.5a

Postby Erik Khong 2E » Wed Feb 21, 2018 5:36 am

In my opinion, it's easier to start with the Br part of the question first. It'll end up being the oxidation half of the reaction, and you can just assume that the O3 part will be the reduction half.


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