calculating oxidation states

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Megan Purl 1E
Posts: 49
Joined: Fri Sep 29, 2017 7:07 am

calculating oxidation states

Postby Megan Purl 1E » Mon Feb 19, 2018 11:13 pm

How do you calculate the oxidation states of compounds within a redox reaction?

Priyanka Bhakta 1L
Posts: 50
Joined: Fri Sep 29, 2017 7:04 am

Re: calculating oxidation states

Postby Priyanka Bhakta 1L » Tue Feb 20, 2018 9:05 am

Look for atoms within the molecule that have a consistent oxidation state. For example, if you have MnO4-, you know that oxygen atoms tend to have a 2- charge, thus Mn must be of 7+ charge to have an overall charge of 1-. You can also try and attain the oxidation state of an atom based on the charges of the half equation since both sides of the equation must be balanced in charge and numbers atoms.

Katelyn 2E
Posts: 35
Joined: Sat Jul 22, 2017 3:01 am

Re: calculating oxidation states

Postby Katelyn 2E » Tue Feb 20, 2018 6:07 pm

These are also some general rules that are really helpful:
The oxidation state of an individual atom is 0.
The total oxidation state of all atoms in: a neutral species is 0 and in an ion is equal to the ion charge.
Group 1 metals have an oxidation state of +1 and Group 2 an oxidation state of +2
The oxidation state of fluorine is -1 in compounds
Hydrogen generally has an oxidation state of +1 in compounds
Oxygen generally has an oxidation state of -2 in compounds
In binary metal compounds, Group 17 elements have an oxidation state of -1, Group 16 elements of -2, and Group 15 elements of -3.


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