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calculating oxidation states

Posted: Mon Feb 19, 2018 11:13 pm
by Megan Purl 1E
How do you calculate the oxidation states of compounds within a redox reaction?

Re: calculating oxidation states

Posted: Tue Feb 20, 2018 9:05 am
by Priyanka Bhakta 1L
Look for atoms within the molecule that have a consistent oxidation state. For example, if you have MnO4-, you know that oxygen atoms tend to have a 2- charge, thus Mn must be of 7+ charge to have an overall charge of 1-. You can also try and attain the oxidation state of an atom based on the charges of the half equation since both sides of the equation must be balanced in charge and numbers atoms.

Re: calculating oxidation states

Posted: Tue Feb 20, 2018 6:07 pm
by Katelyn 2E
These are also some general rules that are really helpful:
The oxidation state of an individual atom is 0.
The total oxidation state of all atoms in: a neutral species is 0 and in an ion is equal to the ion charge.
Group 1 metals have an oxidation state of +1 and Group 2 an oxidation state of +2
The oxidation state of fluorine is -1 in compounds
Hydrogen generally has an oxidation state of +1 in compounds
Oxygen generally has an oxidation state of -2 in compounds
In binary metal compounds, Group 17 elements have an oxidation state of -1, Group 16 elements of -2, and Group 15 elements of -3.