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### Balancing REDOX reactions

Posted: **Tue Feb 20, 2018 10:08 am**

by **Mike Vinci 2B**

When you balance the two equations for the number of electrons, would you multiply the E standard of the two equations by the factor you used to balance the equation, or do they remain the same?

### Re: Balancing REDOX reactions

Posted: **Tue Feb 20, 2018 10:09 am**

by **SitharaMenon2B**

E would remain the same, it's not affected by the amount of electrons

### Re: Balancing REDOX reactions

Posted: **Tue Feb 20, 2018 11:32 am**

by **Justin Lai 1C**

Because Eo is an intensive property, voltage difference is the same and does not depend on how many times the reaction occurs.

### Re: Balancing REDOX reactions

Posted: **Wed Feb 21, 2018 12:17 am**

by **Alejandra Rios 1L**

The value of E should be the same after this is undergone.. there is no need to multiply by the factor.

### Re: Balancing REDOX reactions

Posted: **Wed Feb 21, 2018 1:41 pm**

by **Adrian Lim 1G**

You would not need to multiply E by the factor, but if you were to switch the equation, the E would change sign.

### Re: Balancing REDOX reactions

Posted: **Thu Feb 22, 2018 10:02 am**

by **Nicole Jacobs 1C**

remember not to multiply E by a factor when you are balancing the equations. Unlike H and S, you do not multiply E by the coefficients you use to balance the equations, since E is intensive.