14.3 (a)

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Gavin Kellerman 1D
Posts: 17
Joined: Sat Jul 09, 2016 3:00 am

14.3 (a)

Postby Gavin Kellerman 1D » Tue Feb 20, 2018 5:36 pm

For the oxidation half reaction of thiosulfate the solutions manual shows that there is a loss of 8 electrons, but doesn't that still leave an imbalance in charge from the 2- on the reactants side of the equation?

Lorie Seuylemezian-2K
Posts: 62
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.3 (a)

Postby Lorie Seuylemezian-2K » Tue Feb 20, 2018 8:54 pm

No there is a -2 charge on both sides of the equation.
reactants: 2- from s2o3
products: 4- from so4, 10+ from h, 8e-

Evelyn L 1H
Posts: 67
Joined: Fri Sep 29, 2017 7:05 am

Re: 14.3 (a)

Postby Evelyn L 1H » Wed Feb 21, 2018 2:17 pm

The solutions manual says Cl2 is the oxidizing agent and S2O3 is the reducing agent. But I thought since Cl goes from +0 to -2 it is reduced and S2O3 2- is oxidized because it goes from +4 to +12. Is that a solutions manual error or did I do something wrong?

Evelyn L 1H
Posts: 67
Joined: Fri Sep 29, 2017 7:05 am

Re: 14.3 (a)

Postby Evelyn L 1H » Wed Feb 21, 2018 2:28 pm

Update I figured it out:

it asks for the oxidization/reduction agent not what is being oxidized/reduced.


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