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14.1 D

Posted: Tue Feb 20, 2018 8:10 pm
by Jesse_torres2H
In this question you are supposed to balance the redox equation the answer reads, 8H+ + Cr2O7^2- + 3C2H5OH---> 2Cr^3+ + 3C2H4O + 7H2O. why do you need the 3 in front of C2H5OH and C2H4O

Re: 14.1 D

Posted: Tue Feb 20, 2018 8:50 pm
by Lorie Seuylemezian-2K
This is because we multiply the half reactions with a coefficient in order to cancel out the electrons on both sides.

Re: 14.1 D

Posted: Sat Feb 24, 2018 5:16 pm
by Manasvi Paudel 1A
Before adding half reactions in order to get a final reaction, you have to make sure that there is the same amount of electrons in each half reaction that are being either gained or lost. In order to do that you may have to multiply a half reaction by a certain number, which was done here to get those coefficients.

Re: 14.1 D

Posted: Sun Feb 25, 2018 6:34 pm
by Erik Khong 2E
You need to balance both half reactions in order for them to have equal amount of electrons being gained and lost, so they can cancel out for the final redox reaction.