5 posts • Page 1 of 1
The oxidation number of elements will usually add up to the overall charge of the ion. For example, in MnO4 with a charge of 1-, the oxidation numbers of the atoms must add up to -1. Oxygen will be -2 in most cases, and since there are 4 oxygen atoms, Mn would have an oxidation number of +7. +7 +4(-2) = -1 Mn solid will have an oxidation number of 0 since it is neutral. Hope this helps!
aside from set elements like 0, H, etc, the oxidation number can very depending on the compound. most of the time by knowing that 0 is 2- and H is +1 you can figure out the rest of the oxidation states.
finding the oxidation of a molecule that isn't standard depends entirely upon the the oxidation number of the molecule with standard oxidation values, like O and H. they usually have to equal each other, so just make sure the charges cancel out. hope that makes sense
The overall charge of a molecule is the number charged to it and the end (if there's nothing there, set the charge equal to zero). Then we would use set oxidation values (O = -2, H= 1) and add it to X (or times it by a coefficient) of the oxidation charge we DON't know. Then we set that to the overall charge and solve for X. [In this problem, that would be Mn]. Hope this helps.
Who is online
Users browsing this forum: No registered users and 1 guest