6K.1 7th Edition

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Melody P 2B
Posts: 35
Joined: Fri Sep 29, 2017 7:06 am

6K.1 7th Edition

Postby Melody P 2B » Thu Feb 21, 2019 7:46 pm

H+ + Cr2O72-+C2H5OH ----> Cr3+ + H2O

The oxidized reaction is C2H5OH ---> C2H4O

The solutions manual says C is oxidized from 2- to 1- but when I do the math I get from 2- to 1+ , what am I doing wrong?

Kate Chow 4H
Posts: 61
Joined: Fri Sep 28, 2018 12:28 am

Re: 6K.1 7th Edition

Postby Kate Chow 4H » Thu Feb 21, 2019 9:16 pm

C2H5OH ---> C2H4O
For C2H5OH, you know that there are 6H(+1/H), 1O(-2), 2C(-2/C). Total charge = 0
For C2H4O, you know that there are 4H(+1/H), 1O(-2), which leaves -2 left to be filled by the 2C. Therefore, each C will have a charge of -1 to make the total charge = 0.

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