6K.3d

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Michelle Song 1G
Posts: 30
Joined: Wed Nov 14, 2018 12:23 am

6K.3d

Postby Michelle Song 1G » Sat Feb 23, 2019 8:25 pm

How do you find the half reactions?

Rachana Jayaraman 1H
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am

Re: 6K.3d

Postby Rachana Jayaraman 1H » Sun Feb 24, 2019 12:04 am

Cl2 is both the oxidizing and reducing agent in this case.
The oxidation number of Cl in HClO is +1 and the oxidation number for Cl- is -1.
Therefore the oxidation reaction is Cl2 to HClO in an acidic solution:
Cl2 + 2H2O ---> 2HClO + 2 e- + 2H+
The 2 e- is because each Cl atom loses 1 e- to go from 0 to +1.
The water has to be in the reactants in order to account for the O atoms in the products, and the H+ is to make up for the H atoms from water that are not in HClO as well as to balance the -2 charge from the electrons.
The reduction reaction if Cl2 to Cl-:
Cl2 + 2e- ---> 2Cl-

Michelle Song 1G
Posts: 30
Joined: Wed Nov 14, 2018 12:23 am

Re: 6K.3d

Postby Michelle Song 1G » Sun Feb 24, 2019 1:37 pm

How do you know that Cl2 goes to Cl- when it's not listed in the equation?


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