7th Edit 6L5 c

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Bijan Mehdizadeh 1B
Posts: 73
Joined: Fri Sep 28, 2018 12:15 am

7th Edit 6L5 c

Postby Bijan Mehdizadeh 1B » Sat Feb 23, 2019 8:59 pm

For 6L5 c, how do you determine whether you make the half reaction h2 --> hcl or cl2 --> hcl? There is one product, but cl2 is reduced while h2 is oxidized, so I was wondering how come hcl is only used in the anode half rxn eq for h2

Chloe Qiao 4C
Posts: 65
Joined: Fri Sep 28, 2018 12:27 am

Re: 7th Edit 6L5 c

Postby Chloe Qiao 4C » Sat Feb 23, 2019 9:27 pm

Consider HCl to be H+ and Cl-. The anode side will be H2 and H+, and the cathode side will be CL2 and CL-.

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