Problem 14.1, 6th ed.

Moderators: Chem_Mod, Chem_Admin

Maria Trujillo 1L
Posts: 47
Joined: Fri Apr 06, 2018 11:05 am

Problem 14.1, 6th ed.

Postby Maria Trujillo 1L » Sun Feb 24, 2019 8:58 pm

In problem 14.1, we have to balance the equation in regards to hydrogen and oxygen, but I thought we only needed to balance the elements being oxidized or reduced as well as the electrons. Why do we also need to balance the hydrogens with oxygens? Thank you, the chemical equation is below.
H(+) (aq) + Cr2O7(2-) (aq) + C2H5)H (aq) -----> Cr(3+) (aq) + C2H4O (aq) + H2O (l)

Schuyler_Howell_4D
Posts: 66
Joined: Fri Sep 28, 2018 12:28 am
Been upvoted: 1 time

Re: Problem 14.1, 6th ed.

Postby Schuyler_Howell_4D » Sun Feb 24, 2019 9:19 pm

Could it be that you have to balance oxygen with water so you then have to balance the newly added hydrogens for acidic solutions? And then in the basic solution, you balance the hydrogen by adding water and then have to balance the newly added oxygens?

Just an idea

Matthew Casillas 1C
Posts: 29
Joined: Fri Sep 28, 2018 12:21 am

Re: Problem 14.1, 6th ed.

Postby Matthew Casillas 1C » Sun Feb 24, 2019 10:33 pm

Wouldn't you be balancing oxygen and hydrogen to figure out the overall charge and then balance the charges by adding electrons?

404982241
Posts: 47
Joined: Fri Sep 28, 2018 12:17 am

Re: Problem 14.1, 6th ed.

Postby 404982241 » Sun Feb 24, 2019 11:36 pm

Although the focus is on the molecules being reduced and oxidized, it is still a chemical reaction and all the elements and charges need to be balanced. As we have done in the past there needs to be the same number of hydrogens on both sides and electrons etc.

there are two really good example problems at the beginning of chapter 14 (6th edition)


Return to “Balancing Redox Reactions”

Who is online

Users browsing this forum: No registered users and 2 guests