Homework Question: 6th edition, 14.1

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Bianca Barcelo 4I
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Homework Question: 6th edition, 14.1

Postby Bianca Barcelo 4I » Tue Feb 26, 2019 2:04 am

Can someone help with balancing the redox equation?
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jonathanjchang2E
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Re: Homework Question: 6th edition, 14.1

Postby jonathanjchang2E » Tue Feb 26, 2019 2:33 am

First you separate and balance the two half reactions. The oxidation half reaction is C2H5OH -> C2H4O. You know this because the oxidation number of carbon in the first molecule is -2 and in the product molecule, it's -1. You then balance the half reaction by adding H+ and e- and you should get C2H5OH -> C2H4O + 2H+ + 2e-. Do the same with the reduction half reaction, Cr2O7^2- -> Cr^3+, and combine the two half reactions by adding molecules that are on the same side and crossing out electrons on opposing sides.


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