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Postby Noh_Jasmine_1J » Tue Feb 26, 2019 2:05 pm

how can you tell that Br2(l)-->Br^-(aq) is a reduction? what would the oxidation numbers be?

Fiona Jackson 1D
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Re: Br2(l)-->Br^-(aq)

Postby Fiona Jackson 1D » Tue Feb 26, 2019 2:14 pm

Hi! You can tell that it is reduction because the oxidation number of an element in its pure form, such as Br2 is 0 and then it goes to Br^-. Therefore, the oxidation number goes from 0 to -1, indicating a gain of electrons which is reduction.

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