redox homework question

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Maayan Epstein 14B
Posts: 39
Joined: Fri Sep 28, 2018 12:20 am

redox homework question

Postby Maayan Epstein 14B » Tue Feb 26, 2019 3:53 pm

Hi, in homework question 14.1 in the 6th edition, I am supposed to name the elements that undergo either oxidation or reduction. The answer solution does not include oxygen in it, even though it is oxidized. Can someone explain?
H+ (aq) +cr2o7^2- (aq) +c2H5OH (aq) --> Cr^3+ (aq) + C2H4OH (aq) + H2O (l)

beckyolmedo1G
Posts: 34
Joined: Fri Sep 28, 2018 12:21 am

Re: redox homework question

Postby beckyolmedo1G » Tue Feb 26, 2019 3:56 pm

are you sure that oxygen got oxidized? I thought that it remained the same (-2) on both sides.

kamalkolluri
Posts: 65
Joined: Fri Sep 28, 2018 12:17 am
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Re: redox homework question

Postby kamalkolluri » Tue Feb 26, 2019 4:00 pm

Oxygen isn't in peroxide form anywhere nor is it in O2 form anywhere so it's oxidation number remains at -2. Cr goes from 6+ to 3+ so it is reduced and I think there's a typo in what you wrote, but I remember seeing this problem and Carbon is oxidized.

Albert_Luu3K
Posts: 62
Joined: Fri Sep 28, 2018 12:23 am

Re: redox homework question

Postby Albert_Luu3K » Wed Feb 27, 2019 5:15 am

Oxygen is not being oxidized here. It remains (-2) on both sides. Carbon is being oxidized here.


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