Homework
Posted: Wed Mar 13, 2019 10:57 am
For 6K5d, how do we balance the separate redox equations?
when p4->H2PO2- why do we not add H20 to both sides, how come we just directly add OH-?
Then for P4-> PH3, why don't we add 12H20 to the reactant side and 24 H20 to products then 12 OH- to reactants to balance?
aren't we usually supposed to do those steps first? ^^
when p4->H2PO2- why do we not add H20 to both sides, how come we just directly add OH-?
Then for P4-> PH3, why don't we add 12H20 to the reactant side and 24 H20 to products then 12 OH- to reactants to balance?
aren't we usually supposed to do those steps first? ^^