Can someone help with this question from test 2.
Rank the following species in order of increasing reducing power going from their neutral to second oxidation state: Pt, Pb, Cu.
How do we know this?
Test 2
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Re: Test 2
Rank the following species in order of increasing reducing power going from their neutral to second oxidation state: Pt, Pb, Cu.
How do we know this?
As a general trend, the reducing power of an electrolytic half cell increases as the value of E cell decreases (can be thought of as becoming more negative). In the context of the test question, we are asked to compare Pt, Pb and Cu. To do this, we use the table of standard reduction potentials given.
Standard reduction potential of the Pt half cell = 1.20V
Standard reduction potential of the Pb half cell = -0.13
Standard reduction potential of the Cu half cell = 0.34
Since the most negative value is that of Pb, the Pb half cell is the cell with the greatest reducing power, followed by the Cu half cell, and lastly the Pt half cell.
Therefore, from least to greatest reducing power, the order would be Pt, Cu, Pb.
How do we know this?
As a general trend, the reducing power of an electrolytic half cell increases as the value of E cell decreases (can be thought of as becoming more negative). In the context of the test question, we are asked to compare Pt, Pb and Cu. To do this, we use the table of standard reduction potentials given.
Standard reduction potential of the Pt half cell = 1.20V
Standard reduction potential of the Pb half cell = -0.13
Standard reduction potential of the Cu half cell = 0.34
Since the most negative value is that of Pb, the Pb half cell is the cell with the greatest reducing power, followed by the Cu half cell, and lastly the Pt half cell.
Therefore, from least to greatest reducing power, the order would be Pt, Cu, Pb.
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- Posts: 73
- Joined: Fri Sep 28, 2018 12:16 am
Re: Test 2
Rank the following species in order of increasing reducing power going from their neutral to second oxidation state: Pt, Pb, Cu.
How do we know this?
As a general trend, the reducing power of an electrolytic half cell increases as the value of E cell decreases (can be thought of as becoming more negative). In the context of the test question, we are asked to compare Pt, Pb and Cu. To do this, we use the table of standard reduction potentials given.
Standard reduction potential of the Pt half cell = 1.20V
Standard reduction potential of the Pb half cell = -0.13
Standard reduction potential of the Cu half cell = 0.34
Since the most negative value is that of Pb, the Pb half cell is the cell with the greatest reducing power, followed by the Cu half cell, and lastly the Pt half cell.
Therefore, from least to greatest reducing power, the order would be Pt, Cu, Pb.
How do we know this?
As a general trend, the reducing power of an electrolytic half cell increases as the value of E cell decreases (can be thought of as becoming more negative). In the context of the test question, we are asked to compare Pt, Pb and Cu. To do this, we use the table of standard reduction potentials given.
Standard reduction potential of the Pt half cell = 1.20V
Standard reduction potential of the Pb half cell = -0.13
Standard reduction potential of the Cu half cell = 0.34
Since the most negative value is that of Pb, the Pb half cell is the cell with the greatest reducing power, followed by the Cu half cell, and lastly the Pt half cell.
Therefore, from least to greatest reducing power, the order would be Pt, Cu, Pb.
Re: Test 2
Reducing ability is the ability for a molecule to reduce another molecule and oxidize itself. When ranking these molecules, the ones that will oxidize the strongest are the ones with the lowest standard reduction potential.
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Re: Test 2
the lower the standard reduction potential, the higher the reducing agent, since this means that it oxidizes itself and reduces others
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