## Multiplying by number of elections gained/lost

Jorja De Jesus 2C
Posts: 121
Joined: Sat Jul 20, 2019 12:15 am

### Multiplying by number of elections gained/lost

Why do we multiply the half-reactions by the number of electrons gained or lost?

JohnWalkiewicz2J
Posts: 103
Joined: Thu Jul 11, 2019 12:17 am
Been upvoted: 1 time

### Re: Multiplying by number of elections gained/lost

Lets say you have a simple reaction 5Fe+2 ---> 5Fe+3
In this case, each iron has lost an electron, so to find the total # of electrons lost you multiply electrons lost per molecule by the stoichiometric coefficient. 1x5 = 5 electrons lost.

Rodrigo2J
Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

### Re: Multiplying by number of elections gained/lost

We add certain numbers of electrons depending on the number of electrons gained or lost. l. At least that's what I was taught. I'm sure Dr. Lavelle will cover it more in class.

DLee_1L
Posts: 103
Joined: Sat Aug 17, 2019 12:17 am

### Re: Multiplying by number of elections gained/lost

Are you referring to the number of electrons gained/lost by the opposite half-reaction? In that case, we multiply each half reaction by the amount of electrons gained/lost by the opposite half reaction because then it becomes easy to add the two half-reactions because the amount of electrons gained/lost cancel out and we get a clean equation.