Multiplying by number of elections gained/lost

Moderators: Chem_Mod, Chem_Admin

Jorja De Jesus 2C
Posts: 121
Joined: Sat Jul 20, 2019 12:15 am

Multiplying by number of elections gained/lost

Postby Jorja De Jesus 2C » Sat Feb 15, 2020 11:10 pm

Why do we multiply the half-reactions by the number of electrons gained or lost?

JohnWalkiewicz2J
Posts: 103
Joined: Thu Jul 11, 2019 12:17 am
Been upvoted: 1 time

Re: Multiplying by number of elections gained/lost

Postby JohnWalkiewicz2J » Sun Feb 16, 2020 12:52 am

Lets say you have a simple reaction 5Fe+2 ---> 5Fe+3
In this case, each iron has lost an electron, so to find the total # of electrons lost you multiply electrons lost per molecule by the stoichiometric coefficient. 1x5 = 5 electrons lost.

Rodrigo2J
Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

Re: Multiplying by number of elections gained/lost

Postby Rodrigo2J » Sun Feb 16, 2020 12:58 am

We add certain numbers of electrons depending on the number of electrons gained or lost. l. At least that's what I was taught. I'm sure Dr. Lavelle will cover it more in class.

DLee_1L
Posts: 103
Joined: Sat Aug 17, 2019 12:17 am

Re: Multiplying by number of elections gained/lost

Postby DLee_1L » Sun Feb 16, 2020 2:03 am

Are you referring to the number of electrons gained/lost by the opposite half-reaction? In that case, we multiply each half reaction by the amount of electrons gained/lost by the opposite half reaction because then it becomes easy to add the two half-reactions because the amount of electrons gained/lost cancel out and we get a clean equation.


Return to “Balancing Redox Reactions”

Who is online

Users browsing this forum: No registered users and 2 guests