oxidation states (6K.1)

Moderators: Chem_Mod, Chem_Admin

dtolentino1E
Posts: 101
Joined: Thu Jul 11, 2019 12:17 am

oxidation states (6K.1)

Postby dtolentino1E » Sun Feb 16, 2020 2:20 pm

how do i know the oxidation states of elements in compounds?

for example, in 6K.1, it says that C is oxidized from -2 to 1- in C2H5OH --> C2H4O

SnehinRajkumar1L
Posts: 101
Joined: Thu Jul 11, 2019 12:15 am

Re: oxidation states (6K.1)

Postby SnehinRajkumar1L » Sun Feb 16, 2020 2:35 pm

You would calculate it using the known oxidation states of elements. For example, O is typically -2, C is typically +4, etc. You can use this to calculate this by equating it to the total charge.

Elena Bell 1C
Posts: 64
Joined: Thu Jul 11, 2019 12:16 am

Re: oxidation states (6K.1)

Postby Elena Bell 1C » Sun Feb 16, 2020 2:48 pm

Also, the oxidation states should add up to the total charge of the molecule. In the equation you have, both molecules have a total charge of zero so all the oxidation states of each element should add up to zero. If the molecule has a negative or positive charge, then it should add up to that number.


Return to “Balancing Redox Reactions”

Who is online

Users browsing this forum: No registered users and 1 guest