How do you identify elements that undergo oxidation/reduction in a reaction?
For example, in 6K1 part a, it asks:
Identify elements undergoing oxidation/reduction and indicate their initial and final oxidation numbers for the equation
H+ (aq) + Cr2O7 [2-] (aq) + C2H5OH (aq) -> Cr [3+] (aq) + C2H4O (aq) + H2O (l)
Identifying Elements Undergoing Oxidation/Reduction
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 115
- Joined: Sat Aug 24, 2019 12:17 am
-
- Posts: 102
- Joined: Sat Aug 24, 2019 12:17 am
- Been upvoted: 1 time
Re: Identifying Elements Undergoing Oxidation/Reduction
A good way to remember how to identify elements undergoing oxidation/reduction is
"LEO the lion goes GER"
LEO: Losing Electrons=Oxidation
GER: Gaining Electrons=Reduction
"LEO the lion goes GER"
LEO: Losing Electrons=Oxidation
GER: Gaining Electrons=Reduction
Re: Identifying Elements Undergoing Oxidation/Reduction
You can also look at the element's oxidation number before and after the equation. Elements whose oxidation number increases are oxidized, and vice versa for reduced.
For 6K1:
Given H is typically +1 oxidation and oxygen is typically -2 oxidation number, we can tell that our two elements undergoing change are Cr and C. in Cr2O22-, Cr has oxidation number +6 since O2 is -2. In the products, the Cr number is +3. Cr is reduced.
In the reactant C2H5OH, C has oxidation number -2 (H is +1 and O is -2). In the products, C's oxidation number increases to -1. C is oxidized.
For 6K1:
Given H is typically +1 oxidation and oxygen is typically -2 oxidation number, we can tell that our two elements undergoing change are Cr and C. in Cr2O22-, Cr has oxidation number +6 since O2 is -2. In the products, the Cr number is +3. Cr is reduced.
In the reactant C2H5OH, C has oxidation number -2 (H is +1 and O is -2). In the products, C's oxidation number increases to -1. C is oxidized.
-
- Posts: 115
- Joined: Sat Aug 24, 2019 12:17 am
Re: Identifying Elements Undergoing Oxidation/Reduction
MinuChoi wrote:You can also look at the element's oxidation number before and after the equation. Elements whose oxidation number increases are oxidized, and vice versa for reduced.
For 6K1:
Given H is typically +1 oxidation and oxygen is typically -2 oxidation number, we can tell that our two elements undergoing change are Cr and C. in Cr2O22-, Cr has oxidation number +6 since O2 is -2. In the products, the Cr number is +3. Cr is reduced.
In the reactant C2H5OH, C has oxidation number -2 (H is +1 and O is -2). In the products, C's oxidation number increases to -1. C is oxidized.
Are you ignoring the H+ and H2O in the reactant and product? Do they not matter for this problem?
-
- Posts: 102
- Joined: Sat Aug 24, 2019 12:17 am
- Been upvoted: 1 time
Re: Identifying Elements Undergoing Oxidation/Reduction
I forgot to mention the example in my last post. So for the example in your post, to identify the elements, calculate the oxidation state for each of the elements in the reactants and and for each of the elements in the products and if you use the rules from the previous post you can figure out which elements are going under oxidation and which are going under reduction.
Re: Identifying Elements Undergoing Oxidation/Reduction
Are you ignoring the H+ and H2O in the reactant and product? Do they not matter for this problem?
They don't really matter for part a. To find the oxidation number of a single element in a compound, you don't really need to look at the other reactants. But you will definitely need to consider them for balancing the reaction, which is the rest of the problem. Keep in mind the actual compounds don't change when you balance the reaction; you're just altering the amounts.
Return to “Balancing Redox Reactions”
Who is online
Users browsing this forum: No registered users and 3 guests