We are given the following reaction:
Cl2 (g) --> HClO (aq) + Cl2 (aq)
how come the half reaction with Cl2 is written as
Cl2 (g) + 2e- --> 2Cl-(aq)? if the reaction has Cl2 on both sides of the original equation
6k3 part d
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Re: 6k3 part d
I don't know if it helps or if you already know but there is a typo in the question. The Cl2 on the right side should be Cl- where it says Cl2(g) -> HClO(aq) + Cl2(g)
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Re: 6k3 part d
I had the same question. but I guess if it's a typo then it makes sense. If there were to be Cl2 on both sides of the equation would it be solvable?
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Re: 6k3 part d
JosephineF wrote:I had the same question. but I guess if it's a typo then it makes sense. If there were to be Cl2 on both sides of the equation would it be solvable?
if it had Cl2 on both sides, they would cancel i believe and it wouldn't be solvable. You have to take into account the typo as mentioned above:
"I don't know if it helps or if you already know but there is a typo in the question. The Cl2 on the right side should be Cl- where it says Cl2(g) -> HClO(aq) + Cl2(g)"
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