6k3 part d

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705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

6k3 part d

Postby 705121606 » Mon Feb 17, 2020 1:11 pm

We are given the following reaction:
Cl2 (g) --> HClO (aq) + Cl2 (aq)

how come the half reaction with Cl2 is written as
Cl2 (g) + 2e- --> 2Cl-(aq)? if the reaction has Cl2 on both sides of the original equation

Aliya Jain 2B
Posts: 101
Joined: Wed Sep 11, 2019 12:16 am

Re: 6k3 part d

Postby Aliya Jain 2B » Mon Feb 17, 2020 3:03 pm

I think its because cl2 is used as both the oxidizing and reducing agent

MAC 4G
Posts: 121
Joined: Wed Sep 18, 2019 12:16 am

Re: 6k3 part d

Postby MAC 4G » Mon Feb 17, 2020 4:16 pm

I don't know if it helps or if you already know but there is a typo in the question. The Cl2 on the right side should be Cl- where it says Cl2(g) -> HClO(aq) + Cl2(g)

JosephineF
Posts: 49
Joined: Wed Sep 18, 2019 12:17 am

Re: 6k3 part d

Postby JosephineF » Mon Feb 17, 2020 5:59 pm

I had the same question. but I guess if it's a typo then it makes sense. If there were to be Cl2 on both sides of the equation would it be solvable?

BeylemZ-1B
Posts: 95
Joined: Thu Jul 25, 2019 12:17 am

Re: 6k3 part d

Postby BeylemZ-1B » Tue Feb 18, 2020 1:25 pm

JosephineF wrote:I had the same question. but I guess if it's a typo then it makes sense. If there were to be Cl2 on both sides of the equation would it be solvable?

if it had Cl2 on both sides, they would cancel i believe and it wouldn't be solvable. You have to take into account the typo as mentioned above:

"I don't know if it helps or if you already know but there is a typo in the question. The Cl2 on the right side should be Cl- where it says Cl2(g) -> HClO(aq) + Cl2(g)"


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