Homework 6K.5 Part B

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EthanPham_1G
Posts: 104
Joined: Sat Jul 20, 2019 12:17 am

Homework 6K.5 Part B

Postby EthanPham_1G » Wed Feb 19, 2020 9:05 pm

How do I solve this problem?
Br2(l) -----> BrO3- +Br-

I don't understand how to balance the redox reaction when the Br is in both products.

Christine Honda 2I
Posts: 116
Joined: Sat Sep 14, 2019 12:17 am

Re: Homework 6K.5 Part B

Postby Christine Honda 2I » Wed Feb 19, 2020 9:15 pm

Br is both the oxidizing and reducing agent.
We balance it assuming using the fact that it is an aqueous solution so H2O.

3Br2 + 6OH- --> 5Br- + BrO3- + 3H2O


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