Moderators: Chem_Mod, Chem_Admin

Sara Richmond 2K
Posts: 110
Joined: Fri Aug 30, 2019 12:16 am


Postby Sara Richmond 2K » Sat Feb 22, 2020 8:00 am

Why does the answer key use 2 electrons for the oxidation reaction when the oxidation number only changes by 1? Why does the answer key use 6 electrons for the reduction reaction when the oxidation number only changes by 3?

Angela Patel 2J
Posts: 110
Joined: Sat Aug 24, 2019 12:17 am

Re: 6K.1

Postby Angela Patel 2J » Sat Feb 22, 2020 11:07 am

The oxidation state changes, but there are also a certain number of molecules. So for carbon, even though the oxidation state goes from 2- to 1-, there are 2 carbon molecules so this would involve 2 electrons.

Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

Re: 6K.1

Postby WYacob_2C » Sat Feb 22, 2020 2:29 pm

After balancing the oxidation half-reactions by adding 2H+ ions, the two side of the half-reactions have unequal charge. By adding the 2 e- on the right side of the reaction, it balances out the 2+ charge from the H+ ion.

Posts: 106
Joined: Sat Sep 14, 2019 12:16 am
Been upvoted: 1 time

Re: 6K.1

Postby Veronica_Lubera_2A » Sat Feb 22, 2020 3:33 pm

When determining the number of electrons to place on a side, you have to compare the overall charge on the left and right sides. Generally, let's say for example, there is a higher positive charge on the left side, you would add that number of electrons on the right side to balance the difference in charge.

Return to “Balancing Redox Reactions”

Who is online

Users browsing this forum: No registered users and 1 guest