6K.1

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Sara Richmond 2K
Posts: 110
Joined: Fri Aug 30, 2019 12:16 am

6K.1

Postby Sara Richmond 2K » Sat Feb 22, 2020 8:00 am

Why does the answer key use 2 electrons for the oxidation reaction when the oxidation number only changes by 1? Why does the answer key use 6 electrons for the reduction reaction when the oxidation number only changes by 3?
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Angela Patel 2J
Posts: 110
Joined: Sat Aug 24, 2019 12:17 am

Re: 6K.1

Postby Angela Patel 2J » Sat Feb 22, 2020 11:07 am

The oxidation state changes, but there are also a certain number of molecules. So for carbon, even though the oxidation state goes from 2- to 1-, there are 2 carbon molecules so this would involve 2 electrons.

WYacob_2C
Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

Re: 6K.1

Postby WYacob_2C » Sat Feb 22, 2020 2:29 pm

After balancing the oxidation half-reactions by adding 2H+ ions, the two side of the half-reactions have unequal charge. By adding the 2 e- on the right side of the reaction, it balances out the 2+ charge from the H+ ion.

Veronica_Lubera_2A
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Joined: Sat Sep 14, 2019 12:16 am
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Re: 6K.1

Postby Veronica_Lubera_2A » Sat Feb 22, 2020 3:33 pm

When determining the number of electrons to place on a side, you have to compare the overall charge on the left and right sides. Generally, let's say for example, there is a higher positive charge on the left side, you would add that number of electrons on the right side to balance the difference in charge.


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