Calculating the reaction Gibbs free energy

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vpena_1I
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Calculating the reaction Gibbs free energy

Postby vpena_1I » Sat Feb 22, 2020 12:07 pm

In ∆G*=-nFE*, is n the number of moles of the species that is being reduced?

Shannon Asay 1C
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Re: Calculating the reaction Gibbs free energy

Postby Shannon Asay 1C » Sat Feb 22, 2020 12:09 pm

n refers to the number of electrons that are transferred in the balanced chemical equation.

WYacob_2C
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Re: Calculating the reaction Gibbs free energy

Postby WYacob_2C » Sat Feb 22, 2020 2:21 pm

n refers to the number of moles of e-

Veronica_Lubera_2A
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Re: Calculating the reaction Gibbs free energy

Postby Veronica_Lubera_2A » Sat Feb 22, 2020 3:51 pm

Also keep in mind that n is the number of moles of electrons being transferred in a half reaction, not the total amount of the two balanced reactions.

Lindsey Chheng 1E
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Re: Calculating the reaction Gibbs free energy

Postby Lindsey Chheng 1E » Sat Feb 22, 2020 4:34 pm

vpena_1I wrote:In ∆G*=-nFE*, is n the number of moles of the species that is being reduced?

n is the mols of electrons involved in the total reaction after you balance both half reactions and make sure the charges are balanced as well.

Callum Guo 1H
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Re: Calculating the reaction Gibbs free energy

Postby Callum Guo 1H » Sat Feb 22, 2020 10:38 pm

n is the mole of e-

Nicholas_Gladkov_2J
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Re: Calculating the reaction Gibbs free energy

Postby Nicholas_Gladkov_2J » Sat Feb 22, 2020 11:19 pm

vpena_1I wrote:In ∆G*=-nFE*, is n the number of moles of the species that is being reduced?


In this equation, "n" is referring to the number of moles of e- that are being transferred.
For the half-reactions remember to balance your reaction!

Veronica Lu 2H
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Re: Calculating the reaction Gibbs free energy

Postby Veronica Lu 2H » Sun Feb 23, 2020 1:07 am

n is the number of moles of electrons being transferred


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