balancing in basic solution 6k5 part d

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705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

balancing in basic solution 6k5 part d

Postby 705121606 » Fri Feb 28, 2020 4:55 pm

I learned that for basic solutions we can balance like a acidic solution and once we get our final result we would add the same number of hydroxides to the side with h+ to balance and create water then cancel out the waters on the other side. I didn't have trouble with this strategy but when I got to part d, I got confused as to how we would balance both half reactions as we would an acidic solution because both of the electrons are on one side

705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

Re: balancing in basic solution 6k5 part d

Postby 705121606 » Sat Feb 29, 2020 10:18 pm

I figured out what I did wrong if anyone else is also stuck:

to balance for acidic solutions:
12e- + 12H+ + P4 --> 4PH3
3(8H2O + P4 --> 4H2PO2- + 8H+ +4e-)


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