6K.3 D)

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briannam_1F
Posts: 35
Joined: Wed Sep 18, 2019 12:18 am

6K.3 D)

Postby briannam_1F » Sat Feb 29, 2020 10:19 pm

How is Cl2 acting as both a oxidizing and reducing agent? Also, why does the half-reaction Cl2(g) --> 2Cl-, where did the Cl- come from?

Goyama_2A
Posts: 107
Joined: Sat Aug 24, 2019 12:17 am

Re: 6K.3 D)

Postby Goyama_2A » Sat Feb 29, 2020 10:35 pm

to your first question, I believe that Cl is acting as both a reducing and oxidizing agent because one of the Cls is giving an electron while the other is accepting that electron.
to your second question, I think someone told me that the Cl2 reactant is a typo and that it should be 2Cl
Last edited by Goyama_2A on Sat Feb 29, 2020 10:46 pm, edited 1 time in total.

William Francis 2E
Posts: 101
Joined: Wed Sep 18, 2019 12:20 am

Re: 6K.3 D)

Postby William Francis 2E » Sat Feb 29, 2020 10:41 pm

The Cl- comes from the reduction of Chlorine gas (Cl2+2e--->2Cl-). After you find the oxidation reaction of chlorine, you can determine that it must also be reduced since it is the sole reactant listed. Although Cl- is not in the skeletal equation given, it must be present in the final balanced equation you write as a reduced form of chlorine from Cl2 just as the chlorine in HClO (with an oxidation number of positive one) is an oxidized form of chlorine from Cl2 (here, the chlorine has an oxidation number of zero).


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