Balancing redox (from worksheet 6-8 workshop)

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205007651
Posts: 53
Joined: Tue Nov 13, 2018 12:17 am

Balancing redox (from worksheet 6-8 workshop)

Postby 205007651 » Mon Mar 02, 2020 8:28 pm

Would someone be able to explain to me how they found the half reaction for Cr and then how they balanced the full redox rxn. Thank you so much!

H+(aq) + (Cr2O7)-2(aq) + C2H5OH(aq) ---> (Cr)3+(aq) + C2H4O(aq) + H2O(l)

Kishan Shah 2G
Posts: 132
Joined: Thu Jul 11, 2019 12:15 am

Re: Balancing redox (from worksheet 6-8 workshop)

Postby Kishan Shah 2G » Mon Mar 02, 2020 8:57 pm

Since we know that this is in acidic solution. We also know that Chromium is being reduced, we can conclude that hydrogen ions will be in our reactants and water will be in our products. Also the electrons will be on the reactants side. After we determine what our products and reactants are, we basically balance the equation. That gives us our balanced redox reaction.

205007651
Posts: 53
Joined: Tue Nov 13, 2018 12:17 am

Re: Balancing redox (from worksheet 6-8 workshop)

Postby 205007651 » Mon Mar 02, 2020 9:29 pm

Was there an answer given I can check my work with?


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