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Balancing redox (from worksheet 6-8 workshop)

Posted: Mon Mar 02, 2020 8:28 pm
by 205007651
Would someone be able to explain to me how they found the half reaction for Cr and then how they balanced the full redox rxn. Thank you so much!

H+(aq) + (Cr2O7)-2(aq) + C2H5OH(aq) ---> (Cr)3+(aq) + C2H4O(aq) + H2O(l)

Re: Balancing redox (from worksheet 6-8 workshop)

Posted: Mon Mar 02, 2020 8:57 pm
by Kishan Shah 2G
Since we know that this is in acidic solution. We also know that Chromium is being reduced, we can conclude that hydrogen ions will be in our reactants and water will be in our products. Also the electrons will be on the reactants side. After we determine what our products and reactants are, we basically balance the equation. That gives us our balanced redox reaction.

Re: Balancing redox (from worksheet 6-8 workshop)

Posted: Mon Mar 02, 2020 9:29 pm
by 205007651
Was there an answer given I can check my work with?