6L.9 part a

Moderators: Chem_Mod, Chem_Admin

Malia Shitabata 1F
Posts: 127
Joined: Sat Aug 17, 2019 12:17 am

6L.9 part a

Postby Malia Shitabata 1F » Tue Mar 03, 2020 6:27 pm

Write balanced half reactions for the redox reaction of an acidified solution of potassium permanganate and iron (II) chloride

How do you know which element is going to be in the anode vs cathode?

Kylie Lim 4G
Posts: 110
Joined: Sat Aug 17, 2019 12:15 am

Re: 6L.9 part a

Postby Kylie Lim 4G » Tue Mar 03, 2020 9:32 pm

Since we're not given the cell diagram, I assume that you would determine the anode and cathode by looking up the reduction potentials for the half reactions. The more positive value is more likely to be the cathode because it is a better oxidizing agent and the less positive value will be the anode because it is a better reducing agent. In this case, since MnO4^- has the more positive potential it will be the cathode and Fe^2+ will be the anode.

Posts: 50
Joined: Mon Nov 11, 2019 12:17 am

Re: 6L.9 part a

Postby 205291012 » Tue Mar 03, 2020 10:36 pm

Find the half reactions in the appendix and then compare the cell potential values that are given. Whichever equation has a higher E naught value will be reduced and thus the other will be oxidized.

Return to “Balancing Redox Reactions”

Who is online

Users browsing this forum: No registered users and 1 guest