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Since we're not given the cell diagram, I assume that you would determine the anode and cathode by looking up the reduction potentials for the half reactions. The more positive value is more likely to be the cathode because it is a better oxidizing agent and the less positive value will be the anode because it is a better reducing agent. In this case, since MnO4^- has the more positive potential it will be the cathode and Fe^2+ will be the anode.
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