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For the reaction to be fully balanced the amount of e- on both sides should be balanced. If they are not balanced after balancing O and H then you would multiply one or both half reactions to get equal electrons on each side.
Yes, it believes it would be deemed incorrect because if the electrons are unbalanced that means the charges don't cancel out even though the compounds themselves are equal. Just multiply it to get the common multiple and you'll be good. :)
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