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I'm still kind of confused on that too. I just know that to cancel the electrons out, make sure whatever you end up flipping, you're reduction equation has electrons on the left, and the oxidized equation has electrons on the right
This would depend on the situation given, but generally, you would want to manipulate the equations so that you end up with the standard potential of the cell being positive (the reaction is spontaneous). Use the equation E(cell)=E(electrode on right of cell diagram)-E(electrode on left of cell diagram)
The wording is definitely a little difficult to understand but I am also assuming that you are asking us for which redox hzlf equation to switch the product and reactant sides. I would say that generally, you would want to have the cell potential to be positive in order to allow the system to have spontaneous reaction.
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