Hi, I am stuck on question 18 in this week's sapling. I put Fe+O2+H2O for the reactants and Fe2O3-3H2O for the product, and I get 4Fe+3O2+6H2O⟶2(Fe2O3∙3H2O)+12e-, which is not correct. I am wondering which step did I do wrong.
Sapling Week7&8 #18
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 101
- Joined: Wed Sep 30, 2020 10:01 pm
Re: Sapling Week7&8 #18
Your basic set up should like this:
Fe + O2 +H2O--> Fe2O3∙ 3H2O
You should not need any electrons in this equation because you could just balance it from this equation. So first balance the Fe and then the H2O. After balancing those, then you can balance the oxygens.
Fe + O2 +H2O--> Fe2O3∙ 3H2O
You should not need any electrons in this equation because you could just balance it from this equation. So first balance the Fe and then the H2O. After balancing those, then you can balance the oxygens.
-
- Posts: 106
- Joined: Wed Sep 30, 2020 10:01 pm
Re: Sapling Week7&8 #18
Hi! You don't need to include the electrons in the reaction. Also, don't put parentheses around the Fe2O3∙3H2O(s). Everything else looks right! Hope this helps! :)
-
- Posts: 58
- Joined: Tue Nov 17, 2020 12:19 am
Re: Sapling Week7&8 #18
Why dont you need to balance electrons through half reactions in this equation?
-
- Posts: 108
- Joined: Wed Sep 30, 2020 9:37 pm
Re: Sapling Week7&8 #18
You can balance this equation without the electrons, so you don't need those, and you also don't need the parentheses! :))
Return to “Balancing Redox Reactions”
Who is online
Users browsing this forum: No registered users and 6 guests