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### HW Question Ch #27

Posted: **Mon Oct 03, 2016 10:56 pm**

by **Yuchien Ma 2L**

A lamp rated at 32 W (1 W = 1 J * s^-1) emits violet light of wavelength 420 nm. How many photons of violet light can the lamp generate in 2.0s? How many moles of photons are emitted in that time interval?

I got the first part, 32 J * s^-1 * 2.0 s = 64 J

But I'm confused about the second part. I am given the wavelength and the energy, how do I convert that to number of photons?

Thanks in advance for your help.

### Re: HW Question Ch #27 [ENDORSED]

Posted: **Mon Oct 03, 2016 11:41 pm**

by **Manpreet Singh 1N**

To begin the problem we need to find the energy of the light. So we use the E=(hc)/wavelength

so energy= ((6.626x10^-34 Js)(3x10^8m/s))/(420x10^9m)

I changed the units of wavelenth from nm to m, so that is why I multiplied 10^-9 to the given wavelength.

We get the energy to be about 4.7x10^-19J. I like to think of this value of J/photon because that is what the energy corresponds to, but when we do the equation we leave out the per photon and just keep it at J for simplicity.

amount of photons=Etotal/Ephoton

so now to find the amount of photons by dividing the total energy 64J( which we got by multiplying 34 Js-1 by 2 seconds) by the energy per photon (4.7x10^-19).

amount of photons=(64 J)/(4.7x10^-19)=1.4x10^20 photons.

then moles of photon=(1.4x10^20 photon)((1 mole)/(avagadro's number=6.022x10^23 photons)=2.3x10^4 moles of photons.

hopefully that helps :)

### Re: HW Question Ch #27

Posted: **Tue Oct 04, 2016 9:21 pm**

by **Yuchien Ma 2L**

Thanks for the explanation!

It's so much clearer than the one in the solutions manual :D

### Re: HW Question Ch #27

Posted: **Sun Oct 09, 2016 11:57 am**

by **Sylvia_Cai_3D**

I had a similar question, but I am still confused about how it is 6.022X10^23 photons per mole. Is it just a known constant that just like atoms there are a certain number of photons per mole?

### Re: HW Question Ch #27

Posted: **Mon Oct 10, 2016 3:10 pm**

by **Dan_Jin_1K**

To Sylvia,

One mole is 6.022 x 10^23 of "things". The mole can be 6.022 x 10^23 atoms, which can be said as 1 mol of atoms, or it could be 6.022 x 10^23 donuts, which would be said as 1 mol of donuts.

For this case, 1 mol of photons, just means 6.022 x 10^23 of those "things" (photons), so you'd have 6.022 x 10^23 photons in 1 mol of photons.

### Re: HW Question Ch #27

Posted: **Sun Oct 16, 2016 3:31 pm**

by **Alex_Wagas_3K**

Sylvia_Cai_1A wrote:I had a similar question, but I am still confused about how it is 6.022X10^23 photons per mole. Is it just a known constant that just like atoms there are a certain number of photons per mole?

6.022x10^23 is a constant that can be expressed as per mole of anything. As stated above, it can represent photons per mole or that of a similar nature