## chapter 1 question 27

$c=\lambda v$

Cali Rauk1D
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### chapter 1 question 27

I am trying to find how many proton the lamp can generate in 2 seconds. I know I should use the E=hv equation but I am getting stuck at where to use the 32 Jxs^-1.

Chem_Mod
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### Re: chapter 1 question 27

You need to first calculate the amount of energy in Joules the lamp generates in 2 seconds before you can find the number of photons. Calculating the energy of the lamp is simply $32 \frac{J}{s} * 2 s$ = 64J.

Michaela Capps 1l
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### Re: chapter 1 question 27

Okay so you were right to want to use E=h·ν but you rearrange it because v ("nu" or frequency)=c/λ so we can use E=hc/λ =(6.626·10^-34 Js)·( 2.997·10^8m/s)/ (470·10-9 m)=4.225*10^-19 J. The lamp emits 32J/s so in 2 seconds, the lamp emits (32*2=) 64J. So we use E(per mol of photons)=N(photons)*E. This equation was in the book around the Einstein section. So 64J=N(photons)*(4.225*10^-19 J). N(photons)=1.893*10^20 photons. Multiply the number of photons by Avogadro's to get the moles. (1mole/6.022*10^23 photon)=3.144*10^-4 moles