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### Question 1.15 Rydberg Equation Math Problem

Posted: Wed Oct 11, 2017 10:14 pm
1.15 In the ultraviolet spectrum of atomic hydrogen, a line is observed at 102.6 nm. Determine the values of n for the initial and final energy levels of the electron during the emission of energy that leads to this spectral line.

I used $\frac{1}{\lambda }=R_{H}(\frac{1}{n1^2}-\frac{1}{n2^2})$. Is this the correct equation to use?

I came up with $8.89 \cdot 10^{-10}$
= $(\frac{1}{n1^2}-\frac{1}{n2^2})$.

The power of 10 is wrong and I need guesswork to find the answer. (n1=1, n2=3).

Is there a simpler way that I am missing?

### Re: Question 1.15 Rydberg Equation Math Problem

Posted: Thu Oct 12, 2017 12:29 am
So I used the equation was c/wavelength=R(1/n_1^2 - 1/n_2^2). Essentially, you're using the given wavelength and using c=v*wavelength to find the frequency, and then using v=R((1/n_1^2 - 1/n_2^2) to find n_2. (We also already know n_1 = 1 because a wavelength of 102.6nm is Lyman series