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I think that technically the answer would be 6.0 x 10^-7 m for wavelength. However, it is easier to identify and compare wavelengths if the value is given in nanometers so it would be converted to 600 nm. If you wanted to be specific about sig figs, you could write a bar above the first zero to indicate 2 sig figs, but for this exercise I don't think that it matters.
I also believe that they want us to convert the wavelengths from nm to m, it's another way to practice. For example, you would have to do extra dimensional analysis to solve for energy, wavelength, and frequency since they are not the same units. Just a way to challenge our problem solving skills, I think.
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