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### HW #1.7

Posted: **Wed Apr 11, 2018 3:58 pm**

by **Jamie Reniva 1J**

For homework problem 1.7 letter (A), it gave frequency (v) and the constant is already known (c). We can find the wavelength through this way but it is asking for the final answer in nanometers, what steps do we take to convert the current answer into to nanometers?

Question from the textbook:

"(a) The frequency of violet light is 7.1 1014 Hz. What

is the wavelength (in nanometers) of violet light? (b) When an electron beam strikes a block of copper, x-rays with a frequency of 2.0 1018 Hz are emitted. What is the wavelength (in picometers) of these x-rays?"

### Re: HW #1.7

Posted: **Wed Apr 11, 2018 5:15 pm**

by **Andrew Evans - 1G**

Once you have the wavelength in the standard SI unit (meters), you just have to use dimensional analysis to convert it to nanometers or picometers:

_____ m * (10^9 nm / 1 m) = ______ nm

_____ m * (10^12 pm / 1 m) = _______ pm

.... since there are 10^9 nanometers in every meter and 10^12 picometers in every meter.

â€“Andrew Evans

Section 1G

### Re: HW #1.7

Posted: **Sat Apr 21, 2018 7:55 pm**

by **Yadira Flores 1G**

I'm still having trouble with the conversion part of the question. Can anyone show me the steps for the conversion?

### Re: HW #1.7

Posted: **Sat Apr 21, 2018 8:19 pm**

by **SammiOrsini_1B**

I think i am a little confused too. I thought there were 10^-9 meters in a nanometer and 10^-12 meters in picometer.

### Re: HW #1.7

Posted: **Sun Nov 03, 2019 5:36 pm**

by **Aman Sankineni 2L**

SammiOrsini_1B wrote:I think i am a little confused too. I thought there were 10^-9 meters in a nanometer and 10^-12 meters in picometer.

This should be right. Use dimensional analysis with these numbers in order to convert from meters to nanometers/picometers.

### Re: HW #1.7

Posted: **Sun Nov 03, 2019 9:08 pm**

by **Cynthia Rodas 4H**

Part a:

So in order to convert the answer from meters to nanometers, you would try to cancel out the meters in order to get nm by itself. For example:

This would leave the result as 422 nm.

Part b:

This follows the same concept as Part a, only it would be:

which would give you 150 pm.