$c=\lambda v$

megangeorge-1K
Posts: 59
Joined: Thu Feb 01, 2018 3:01 am

in lecture today, Dr. Lavelle mentioned something about having to divide by avogadro's number when regarding the energy it takes to remove an electron. I'm not quite sure why it is we have to divide by avogradro's number or when we would have to. I'm also not sure if this question makes any sense lol.

Thank you!

Sollie1G
Posts: 31
Joined: Wed Nov 08, 2017 3:00 am

I found this but I'm not sure if it is enough to answer your question

"The initial energy state is 1 (the only energy state the hydrogen atom can have) and the inverse of 1 is 1. The difference between 1 and 0 is 1. ... This is the first ionization energy of the hydrogen atom. Multiply the ionization energy by Avogadro's number, which gives the number of particles in a mole of substance."

Liliana Rosales 1E
Posts: 36
Joined: Wed Nov 15, 2017 3:03 am

Dr. Lavelle was saying that we would have to divide the energy by the avogadro's number because the energy is usually given per mole. For problems dealing with the photoelectric effect, you would want to find the energy per photon not per mole. I hope this somewhat clarifies your question.

EllenRenskoff-1C
Posts: 32
Joined: Fri Apr 06, 2018 11:04 am

Did Dr. Lavelle mention if it will be specified in the problem whether we are looking for energy per photon versus energy per mole of photon, or is it implied that it's per photon when we're talking about the photoelectric effect? (I hope my question makes sense.)

Jose Hernandez 1D
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Joined: Tue Nov 14, 2017 3:02 am

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