## HW 1.5 [ENDORSED]

$c=\lambda v$

Mariah Guerrero 1J
Posts: 32
Joined: Fri Apr 06, 2018 11:03 am

### HW 1.5

Question 1.5 states to arrange the following types of photons of electromagnetic radiation in order of increasing energy y rays, visible light, ultraviolet radiation, microwaves, x rays. I understand the order of increasing energy is y ray, x ray, ultraviolet, visible, infrared, microwave and radio. However, can someone further explain why and how the colors of photons of electromagnetic radiation relate to the wavelengths. Also, what is the difference between infrared and visible energy?

Vivian Gonzalez 1A
Posts: 30
Joined: Fri Apr 06, 2018 11:03 am

### Re: HW 1.5  [ENDORSED]

A photon is characterized by either a wavelength(lambda) or equivalently an energy(E). The energy of each photon is inversely related to the wavelength of the associated EM wave.

Neha Divi 1K
Posts: 31
Joined: Fri Apr 06, 2018 11:02 am

### Re: HW 1.5

The colors of photons of the electromagnetic radiation refer to visible light and the different colors that you see. Visible light ranges from 700nm (red light) to 400 nm (violet light) which has a spectrum of colors within that range. The wavelengths represent the different regions of the spectrum and in the case of visible light, it is the only region where our eyes can detect the electromagnetic radiation. Infrared is characterized by a longer wavelength on the spectrum and is within a region that our eyes cannot detect.