Wavelength and frequency proportions [ENDORSED]

[Betty Wolkeba section 1L]

Can someone clarify what Professor Lavelle was talking about in lecture about the wavelength and frequency relationships. For example, why is it when the frequency doubles, the wavelength halves? I'm still a little confused on this concept.

[Kara Justeson 1B]

The equation is c=hv (speed=wavelength x frequency). Since c (speed) is a constant if wavelength decreased, frequency would have to increase in order for the constant c to remain the same (3.00 x 10^8). Essentially, the wavelength and frequency have to equal the constant c when they're multiplied together, so their relationship works like that in order for the constant of speed to remain at it's value. Hope that makes sense!

[arina_m 1A]

What Dr. Lavelle was drawing attention to was the relationship in which wavelength and frequency are inversely proportional to one another. This is why when one is equal to 2 the other is equal to 1/2. You can think of it as v=1/lamda (sorry I don't have the symbol) or frequency=1/wavelength.

[Julia Jones 1G]

wavelength and frequency are inversely proportional but energy and frequency are proportional to each other. the frequency can be thought of as 1/wavelength

[anishathomas]

When wavelength gets bigger, the frequency decreases. If you look at the equation v=f(lambda) and we know that there is constant speed(at least in the same medium) then we know that if one increases, the other has to decrease. Therefore, it is an indirect relationship.

[lukezhang2C]

The two have an inversely proportional relationship, this property is just derived from the formula!