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Wavelength/frequency

Posted: Sun Apr 22, 2018 9:57 pm
by paulacamara1E
Why does energy decrease when wavelength increase? My TA explained the concept in discussion but I don't think I fully got it.

Re: Wavelength/frequency

Posted: Sun Apr 22, 2018 9:59 pm
by Chem_Mod
When wavelength increases, the EM radiation's frequency decreases. Since energy of a photon is E = hv, energy of the photon must decrease since frequency v decreased.

Re: Wavelength/frequency

Posted: Sun Apr 22, 2018 10:01 pm
by Michael Park
Energy = [(Planck's Constant) x (Speed of light)] / [wavelength]

Because wavelength is in the denominator, as the wavelength increases, energy decreases.

Re: Wavelength/frequency

Posted: Sun Apr 22, 2018 10:05 pm
by fara valdez
I guess it's the conservation of energy, if the speed changed then this would require an acceleration which would need energy to be put in or taken out of the wave.

Re: Wavelength/frequency

Posted: Sun Apr 22, 2018 10:06 pm
by Chem_Mod
It is not conservation of energy.

Re: Wavelength/frequency

Posted: Sun Apr 22, 2018 10:06 pm
by Miya Lopez 1I
Increasing the wavelength decreases the kinetic energy of ejected electrons because when you have E=hv, and you substitute in the frequency (v) as c/(lambda) you get.. E= h * c/(lambda).

So when you increase the wavelength, lambda, it makes the fraction c/(lambda) a smaller number overall which means the energy decreases.

I hope the way I explained it makes sense and helps.

Re: Wavelength/frequency

Posted: Wed Apr 25, 2018 6:52 pm
by Daniel Cho Section 1H
It is good to think of it with the equation E=(Planck's constant)(frequency) and speed of light=(wavelength)(frequency). An important skill is linking these two equations together.
Let's try solving for frequency with the equation speed of light=(wavelength)(frequency) which the equation would end up being frequency=(speed of light)/(wavelength). Since E=(Planck's constant)(frequency) you can substitute frequency with the equation we just manipulated which would up being E=((Planck's constant)(speed of light))/(wavelength).

Energy increases as wavelength decrease because of the idea of these two variables being inversely proportional as demonstrated by the equation we just manipulated.

I hope this helps, correct me if I am wrong in some places.

Re: Wavelength/frequency

Posted: Sun May 06, 2018 7:03 pm
by Elana Weingord 1C
It is important to note that when the wavelength increases, the electro magnetic radiation's frequency decreases. Since energy of a photon is expressed through the formula E = hv, energy of the photon must decrease since frequency decreased.

Re: Wavelength/frequency

Posted: Sun May 06, 2018 7:44 pm
by Phil Timoteo 1K
Because E=hv and if the wavelength increases that means the frequency would decrease.

Re: Wavelength/frequency

Posted: Sun May 13, 2018 11:11 pm
by Jose Hernandez 1D
Because E=hc/lambda wavelength is the denominator and the greater the wavelength means the less energy you have since the variables h and c are constants.

Re: Wavelength/frequency

Posted: Mon May 14, 2018 3:50 pm
by KristinaNguyen_1A
Energy decreases when wavelength increases because as wavelength increases, the wave frequency decreases (due to the fact that they are inversely proportional) because larger wavelength means fewer waves. Wave frequency gives off energy so if wavelength increases=frequency decreases, then energy also decreases.

Re: Wavelength/frequency

Posted: Mon May 14, 2018 7:00 pm
by Maria Zamarripa 1L
conceptually, I think it's because since the wavelength is longer there are fewer cycles per second so it is moving slower and has less energy.