Rydberg Formula for Atomic Hydrogen  [ENDORSED]


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Cindy Nguyen 1L
Posts: 48
Joined: Fri Apr 06, 2018 11:04 am

Rydberg Formula for Atomic Hydrogen

Postby Cindy Nguyen 1L » Tue Apr 24, 2018 1:41 pm

On the front page of Test 1, the Rydberg Formula is . In lecture, it is . I was wondering how the formula on Test 1 is equivalent to the one given in lecture.

LilianKhosravi_1H
Posts: 32
Joined: Fri Apr 06, 2018 11:03 am

Re: Rydberg Formula for Atomic Hydrogen

Postby LilianKhosravi_1H » Tue Apr 24, 2018 3:19 pm

The one on my cover of test 1 is -(hR/n^2), which is the same as the one given in lecture.

Sarah Brecher 1I
Posts: 31
Joined: Fri Apr 06, 2018 11:02 am

Re: Rydberg Formula for Atomic Hydrogen

Postby Sarah Brecher 1I » Thu Apr 26, 2018 9:25 pm

While the test will give you the E(n) = -(hR)/n^2, a faster equation that I was given in discussion that is very helpful is:

v (frequency) = R [(1/nf^2) - (1/ni^2)]

Endri Dis 1J
Posts: 33
Joined: Fri Apr 06, 2018 11:02 am

Re: Rydberg Formula for Atomic Hydrogen

Postby Endri Dis 1J » Thu Apr 26, 2018 10:56 pm

There are actually many forms of Rydberg formula given but the one that I use is

DeltaE = -R*((1/nf^2)-(1/ni^2))*Z^2

Where
DeltaE= diff in energy between the final and initial energy level(J)
R= Rydberg"s compound(2.178X10^-18J)
nf= final energy level
ni= initial energy level
Z=atomic# (# of protons)


Also, Rydberg's constant can be written as

2.178X10^-18J
3.29X10^15s^-1
1.097X10^7m^-1

Erin Li 1K
Posts: 30
Joined: Fri Apr 06, 2018 11:03 am

Re: Rydberg Formula for Atomic Hydrogen  [ENDORSED]

Postby Erin Li 1K » Sat Apr 28, 2018 1:04 am

it's E(n) = -(hR)/nfinal^2 -(hR)/ninitial^2
and for frequency it is = R [(1/nfinal^2) - (1/ninitial^2)]


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